(-12(x^2))+46x+70=0

Solution for (-12(x^2))+46x+70=0 equation:

(-12(x^2))+46x+70=0

We get rid of parentheses

-12x^2+46x+70=0

a = -12; b = 46; c = +70;
Δ = b2-4ac
Δ = 462-4·(-12)·70
Δ = 5476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5476}=74$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-74}{2*-12}=\frac{-120}{-24}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+74}{2*-12}=\frac{28}{-24}
=-1+1/6
$